![]() Space Complexity : O(1), as only temporary variables are being created. Time Complexity : O(n), as list traversal is needed. In the end, after the full traversal, the prev will be our head.After pointing to previous, we will make the prev equal to the current, and current equal to the next.Now, make next of current point to prev.Traverse through the list till current becomes null.The prev will initially point to null and current will point to head.Finally we will make prev equal to current, and current equal to next.īy performing the above operations, we are changing the links of every node and ultimately reversing the list. For every node, we are going to store the next of current in next and then will make the next of current point to prev.Now, we have to traverse through the list till the current becomes null.prev will initially point to null and the current will point to the head of the list.Create two nodes, say, prev and current.The approach is going to be pretty simple: The only change will be that we will be changing the links of each node. We have to make use of list traversal in the question. So, the final reverse linked list will beĮxplanation: The input list has been reversed. So to reverse the linked list, we will have to change the links of all the nodes of linked list such that:Ģ7 will now become the new head of the linked list. Here we have to reverse this linked list. Let’s try to understand this problem statement with help of examples. In this question, we are given a singly linked list. Having a good grasp of Linked Lists can be a huge plus point in a coding interview. ![]() The linked list is one of the most important concepts and data structures to learn while preparing for interviews. ![]()
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